How do you get two indexes from index in list block?

[Faraz_Firoz]

How to get two indexes from index in list block
Suppose this is a lost 7555,5643,7555,5432
Here I have used 7555 two times I want to get indexes of both these two 7555.
Anyone please give me idea how can I do this

[Aarush_Kumar]

@Faraz_Firoz

Here I have used 7555 two times

you can remove that old item so that the index in list catches the next number

[gordonlu310]

From this, we know that the list selects the first item among similar items.

So, you can use the following blocks.

[dora_paz]

RE: How To Determine Index of Duplicate Items in a List

I had a little play with this. based upon the topic title (and the other topic running on this one). My effort takes a simple list that contains duplicates, makes a list of lists using the indexes of each item, then returns the set of unique items in the list and a set of duplicate entries (but not the first of each duplicate) [image] [blocks (26)]

[Faraz_Firoz]

Thank you @gordonlu310 I will try it

[gordonlu310]

Updated blocks, please read again.

[TIMAI2]

You need to use the for each number block to iterate over a list with duplicates. The for each item block will return the first instance of a duplicate.

[ABG]

This is a good place to use a value function:
indices.aia (2.1 KB)

P.S. These blocks can be dragged directly into your Blocks Editor workspace.

See A way to group projects by theme - #10 by ABG
for a demo.

[ChrisWard]

I think ABG's solution is the most efficient.