I try to pass an URL with Parameters in WebViewer. This does not work. If I omit this parameters URL can be shown. With the parameter ID I get the following runtime error. I testet HTML file on PC Browser and it works.
java.lang.IllegalArgumentException: URI has a query component at java.io.File.<init>(File.java:435) at com.google.appinventor.components.runtime.util.FileUtil.openFile(FileUtil.java:315) at com.google.appinventor.components.runtime.Form.openAssetInternal(Form.java:3088) at com.google.appinventor.components.runtime.Form.openAsset(Form.java:3049) at com.google.appinventor.components.runtime.util.HoneycombWebViewClient.handleAppRequest(HoneycombWebViewClient.java:65) at com.google.appinventor.components.runtime.util.HoneycombWebViewClient.shouldInterceptRequest(HoneycombWebViewClient.java:50) at WV.wg.a(chromium-SystemWebViewGoogle.aab-stable-772713701:103) at org.chromium.android_webview.ShouldInterceptRequestMediator.shouldInterceptRequestFromNative(chromium-SystemWebViewGoogle.aab-stable-772713701:18)
Note: You will not see another error reported for 5 seconds.
Thanks for your AddOn I put all together to my personal WiKi-Document (meanwhile I have serval ones…: JavaScript, AI2, Arduino, C++, FreeCAD, general technical stuff, VBA…