Index of same items in a list

[Itjustmifdhal]

Hello, I've been tinkering with MIT App inventor and it was a lot of fun. But of course I've some misunderstanding about some usage of the blocks. Especially when I am doing list involving indexes. As for example, I have a list of number {1,0,1,1} and as suppose its indexes are (in order) {1,2,3,4}. If I were to multiply each number in the list with its index, it should be like this: (1x1)+(0x2)+(1x3)+(1x4) right? But my program did it like this: (1x1)+(0x2)+(1x1)+(1x1). I might have some trouble figuring out this. Does anyone can help me on this.

[MohamedTamer]

@Itjustmifdhal

Oh I'm sorry about the misunderstanding.What I meant was (1X1)+(0X2)+(1X3)+(1X4)=8 and (1X1)+(0X 2)+(1X1)+(1X1)=3.

Yes i think now i understand you
Here is how it should be:
this one if you gave it (1 0 1 1 ) and ( 1 2 3 4 ) the output will be 8

And if you want to get how the code make it as string (for debugging):

It will return (11)+(02)+(13)+(14)
Is this what you want?

[Itjustmifdhal]

Yes.But can I know what is in the global list 1 and 2.I'm a bit confussed.

[MohamedTamer]

List one will be something like:

List 2 will be:

[Itjustmifdhal]

Actually i want the numbers {1,0,1,1} to be multiply by its index not items in a list.

[MohamedTamer]

@Itjustmifdhal

index

Okay now i understand you, so no need for list2.You can try this one:

As far as i understand from your question you want something like(from your post)

(1X1)+(0X2)+(1X3)+(1X4)=8

And that's the output here:

[TIMAI2]

ummm, see here @MohamedTamer

Sorting numbers and multiply each numbers

[Itjustmifdhal]

But if there are same items,the index will be the same as the 1st.For example, {1,1,0}. First1 =1,second1=1...

[MohamedTamer]

Nope,My method won't do that.Becuase i don't use index in list method.I use the number variable directly.Just try it!

[Anke]

As @MohamedTamer said, try this:

Similar to this:

Sorting numbers and multiply each numbers

[grafik]

[Itjustmifdhal]

I already try it.However, somehow the result is different.Just like this:

Sorting numbers and multiply each numbers

Hello, I'm very new in MIT apps inventor.I still don't understands few blocks and how to use them.So,I have a question.Can anyone tell me how to make an instruction on how to calculate each digit of a number and can you show me have to do it .I want to make the apps to multiply each digits by a number wanted by the users and sum all of it.For example, if the user enters "2351" and multiply by "2" it will be "2×2+3×2+5×2+1×2=(4)+(6)+(10)+(2)=22".Thank you for reading this:)

I do get "72" when entered "2351" but when I entered "1011" the answer was wrong.I supposed to get "26",but instead i get "6".I've check why it happened.This is because the 2nd and the 3rd "1" index followed the 1st "1". (1×2^1)+(0×2^2)+(1×2^1)+(1×2^1)=6.I hope you can help me.TQ

[ABG]

Please export your project and post it here.

[ABG]

@Itjustmifdhal

This is because the 2nd and the 3rd "1" index followed the 1st "1". (1×2^1)+(0×2^2)+(1×2^1)+(1×2^1)=6.

You lost your place counting from 1 to 4.
It is supposed to be
(1×2^1)+(0×2^2)+(1×2^3)+(1×2^4)=
2 + 0 + 8 + 16 = 26

[Itjustmifdhal]

BASE_N_2020.aia (110.6 KB)

[Itjustmifdhal]

Yes, it is supposed to be like that.But, it didn't.

[ABG]

You used the wrong for each block type.
AI2 does not do a good job of offering the for each number block up from the palette.
Here are corrected blocks, draggable

and proof it works.

[Anke]

Or more compact: BASE_N_2020a.aia (110.6 KB)

[Itjustmifdhal]

Thank you.I will change the block and try it.

[Itjustmifdhal]

Thanks! I already get the answer .Sorry for causing some troubles.