How to get the value of gps module expecially longitude and latitude and display to the web using Nodemcu ESP8266

MIT App Inventor Help
1

This is the code for GPS module using Nodemcu Esp8266 (Access Point)

        #include <ESP8266WiFi.h>
        #include <WiFiClient.h> 
        #include <ESP8266WebServer.h>
        #include <TinyGPS++.h>
        #include <SoftwareSerial.h>
        const char* host = "GPS_NodeMCU";
        const char* ssid = "GPS_BOT";
        String latitude, longitude;
      #define RXPIN 4
#define TXPIN 5
SoftwareSerial ss(RXPIN, TXPIN); // The serial connection to the GPS device
        ESP8266WebServer server(80);
        TinyGPSPlus gps;
        void setup() {
          Serial.begin(115200);
        // Connecting WiFi

         WiFi.mode(WIFI_AP);
          WiFi.softAP(ssid);
        // Starting WEB-server
         server.on ( "/", HTTP_handleRoot );
         server.onNotFound ( HTTP_handleRoot );
         server.begin();    
        }
        void loop() {
          server.handleClient();
           delay(50);
           while (ss.available() > 0){
            gps.encode(ss.read());
            if (gps.location.isUpdated()){

         latitude = "Latitude = " +(gps.location.lat(), 6);

           longitude = "Longitude = " +(gps.location.lng(), 6);
            }
          }
        }
        void HTTP_handleRoot(void) {
          server.send(200, "text/plain", latitude + "," + longitude);

        if( server.hasArg("State") ){
           Serial.println(server.arg("State"));
          }
          server.send(200,"text/html","" );
        }

But my output is

output
output1682×900 124 KB

How to get the value of latitude and longitude using a GPS module and display to the web. But in my case I can’t display the value. What I did wrong in my code?

2

Maybe your local network is 192.168.1.X and the ESP8266 network 192.168.4.X. Different networks.

3

But sir they are the same network.

4

Does this code work for you?
#include <ESP8266WiFi.h>

const char *ssid = "ESP8266_RED";
//const char *password = "123456789";
 
IPAddress ip(192, 168, 4, 2);
IPAddress gateway(192, 168, 4, 1);
IPAddress subnet(255, 255, 255, 0);

WiFiServer server(80);
int random_number = 1;
void setup()
{
   Serial.begin(115200);
   delay(10);
   Serial.println();
 
   WiFi.softAP(ssid);
   WiFi.softAPConfig(ip, gateway, subnet);
   Serial.print("Iniciado AP:\t");
   Serial.println(ssid);
 
   Serial.print("IP address:\t");
   Serial.println(WiFi.softAPIP());
   
   server.begin();
}
 
void loop() {
  random_number=random(1,100);
   // Consulta si se ha conectado algún cliente.
  WiFiClient client = server.available();
  if (!client) {
return;
  }

  Serial.print("Nuevo cliente: ");
  Serial.println(client.remoteIP());

  // Espera hasta que el cliente envíe datos.
  while(!client.available()){ delay(1); }


  
  //////////////////////////////////////////////
  // Página WEB. ////////////////////////////
  client.println("HTTP/1.1 200 OK");
  client.println("Content-Type: text/html");
  client.println(""); //  Importante.
  client.println("Aleatorio: ");
  client.println(random_number);
  Serial.print("Cliente desconectado: ");
  Serial.println(client.remoteIP());
  client.flush();
  client.stop();
  
  }
5

There is two thing that can cause this.

  1. The latitude and longitude string is empty for some reason(gps code, gps connection...).
  2. If i 'm not mistaken, then the send method is not happy if you use other than a simple variable name, but not sure.
    Try to make the final string before the send and send that.
    Like:

string message = latitude + "," + longitude;
server.send(200, "text/plain", message);