Just use :
OnButton1.Click{
Set(Textbox2.Text) = TextBox1.Text
}
And you are done with your Project.
Please mark as Solution if this was the one. 
I'm imagining that Button1 is your Convertir Button.
1 Like
Isn't that just copying from one box to the other without conversion?
But the TextBox actually itself converts numbers and characters into text.
He just wanted input in numbers from TextBox1 and output in Text in TextBox2, so that's what exactly happens in what I said.
How will that help? To the user, a number and a string are no difference. The OP probably wants to convert numbers to English numerals, e.g. one, two, three, or encode them to numbers.
OK then.
I'm making an aia for him.
Please wait.
If you want help, you need to be clear about what you mean by convert number to letter.
-
#Free Word to Number and vice versa any language translator converts a number to a word.
-
Discussion about several ways to convert a word to a number App that converts from letters to numbers.
-
or possibly you want to convert a number to a letter as part of an encryption app.
You might provide an example about what you would like to do.
3 Likes
If you want to make the numbers like -
for number - 10
return - one zero
then its easy (that's already done by me), else if you want returns like 10 it would be quite complicated.
I think I can make it though, but you may not be able to understand because you said :
1 Like
I'm working on
Option 2
Example :
On an input of the number : 2386
Output would be : two thousand three hundred eighty six
I'm not close to success though, but thinking of things.
If you are allowed to use an extension then this extension can be useful for you.
(I think this extension works offline too)
1 Like
@oseamiya Thanks
But I'm planning to do it all by myself.
Cuz, that has allowed me do things that are not present in MIT AI2 by default. These are important procedures (methods) such as,
String s = "Hello World!"
// (1)
s.IndexOf('e');
// (2)
boolean b1 = s.matches("Hello World!"); // true
boolean b2 = s.matches("Hi"); //false
And some more useful operations.
According to me this will help many users.
So I'm gonna do this project all by myself.
I'm first doing this in Java.
Next, I'll copy the whole thing in the form of MIT App Inventor 2 Blocks.
um...
3 Likes
I said String.indexOf();
The method which returns an int value.
or rather you may think it as String.charAt(); method.
Also, I said String.matches(String);
Which returns true if both the Strings are same.
How could you find a String.contains(String); method in my post ? 
So, you can can find java codes if you search on google and you can try creating it through blocks.
3 Likes
Here is also a Stack Overflow answer. (also with numbers to 
French words)
1 Like
Thanks @oseamiya and @Gordon_Lu
But, I didn't see that before actually. 
Had to do it all by myself.
At last the java code is done.
Its 1:57 AM here and I think now its time to get to sleep after this success.
BTW, my program can convert any long value to words, both in negative and positive (not decimals).
Also, BTW, long values go till pentillions.
Conversion
(1 pentillion = 1000000 trillion)
I took me quite a lot of thinking and two days to make it in java.
And I know putting it in MIT AI2 would be a hard task too.
But I'm gonna do it. (Obviously after some sleep, cuz I mentioned the present time.)
Bye. 
Here is the Java Program :
package Practice.Program;
public class Num2Words {
private static long number;
private static String words = new String("");
public Num2Words(long n){ number = n; }
static String[] tp = {"", "thousand ", "million ", "billion ", "trillion ", "quadrillion ", "pentillion "};
static String[] od = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
static String[] td = {"ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"};
static String[] tn = {"", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"};
public String toWords(){
words = Long.toString(number);
int l = words.length();
boolean n = false;
if (number < 0){ n = true; number *= -1; --l;}
breaker : for (byte LOL = 0; LOL < 1; LOL++){
if (StringHasChar(words, '.')){ words = "Decimals not supported."; break breaker;}
if (l>19){ words = "too big"; break breaker;}
if (l==1) words = oneDigit(number); // one digit
else if (l==2) words = twoDigits(number); // two digits
else if (l==3) words = threeDigits(number); // three digits
else words = nDigits(number); // multiple digits
}
if (n == true) {words = "Minus "+words; number *= -1;}
return words;
}
private static String oneDigit(long n){
char[] ns = Long.toString(n).toCharArray();
return od[(char2num(ns[0]))];
}
private static String twoDigits(long n){
String s = "";
char[] ns = Long.toString(n).toCharArray();
if (n < 20){
s = td[(char2num(ns[1]))];
} else if (n < 100){
s = tn[char2num(ns[0])];
if (char2num(ns[1])!=0){ s += " " + od[char2num(ns[1])]; }
}
return s;
}
private static String threeDigits(long n){
String s = "", is = Long.toString(n);
long[] ns = String2longArray(is);
s = od[(int)(ns[0])] + " hundred";
if (ns[1]!=0&&ns[2]!=0){
long i = (ns[1])*10+(ns[2]);
s += " " + twoDigits(i);
} else {
if (ns[1]!=0) s += " " + twoDigits((ns[1]*10));
if (ns[2]!=0) s += " " + oneDigit(ns[2]);
}
return s;
}
private static String nDigits(long n){
String s = threeDigits(n);
int tpi = ((digits(n)+2)/3)-1, rtpi = 0;
long[] tfr = threeFromRight(n);
s = "";
for (; tpi >= 0; tpi--, rtpi++){
s = new Num2Words(tfr[tpi]).toWords() + " " + tp[rtpi] + s;
}
return s;
}
private static int digits(long n){
long ans = 0;
for (; n>0; n/=10, ans++);
return (int)(ans);
}
private static long[] threeFromRight(long n){
int tpi = (digits(n)+2)/3, nl = digits(n);
long[] ans=new long[tpi], ia=String2longArray(Long.toString(n)), ta=new long[3];
for (int i=nl, t=2, c=0, l=tpi*3; l >= 0; l--, c++, i--, t--){
try {ta[t] = ia[i-1];}
catch (ArrayIndexOutOfBoundsException e){ta[t]=0;}
if (((c+1)%3)==0){
--tpi;
ans[tpi] = longArrays2long(ta);
t = 3;
c = -1;
}
}
return ans;
}
private static int char2num(char c){
char[] ca = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
byte ia[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}, ans = -1;
for (byte i = 0; i < 10; i++){ if (c == ca[i]){ ans = ia[i]; break;} }
return ans;
}
private static long[] String2longArray(String s){
char[] ca = s.toCharArray();
byte l = (byte)s.length();
long[] ans = new long[l];
for (byte i = 0; i < l; i++){ ans[i] = char2num(ca[i]); }
return ans;
}
private static long longArrays2long(long[] ia){
long ans = 0;
try { for (int i = 0; i >= 0; ans += ia[i], ans *= 10, ++i); }
catch (ArrayIndexOutOfBoundsException e){}
ans/=10;
return ans;
}
private static boolean StringHasChar(String s, char c){
char[] sca = s.toCharArray();
byte l = (byte)(s.length());
boolean ans = false;
for (byte i = 0; i > l; i++){
if (sca[i] == c) ans = true;
}
return ans;
}
public static void main(String[] args){
long n = -1053664648543756767l;
String words = new Num2Words(n).toWords();
System.out.println(n + " : " + words);
}
}
I've also posted my program as an answer to a question in Stack Overflow.
Would anyone like to help me out with putting some procedures into MIT AI2 ?
If Yes
How you can help me :-
- Make an aia.
- Make the procedures.
- Send the aia.
Helping me is fully your own wish. I'd not force anyone.
Thank You.
Why do you put your code in a stack overflow question from 2011! that is about converting a number to word in Iphone?
2 Likes
Didn't see the date actually. 
Actually, a lot of Stack Overflow Java questions are old, some are the same age or just a year smaller than my age.
Back to the topic, I am making an extension out of this.
EDIT: Wait a minute...seems that there is something wrong in the code.
2 Likes
LOL 
Same with me too, I'm just about to be 15, and these questions are almost 13 years old LOL.
Noice.