As per the [Guide] How to use the CLOCK guide, here are 2 simple ways to check if a year is a leap year or a common year.
The question is also available here.
Definition of a leap year
Before we begin, you need to know the following.

2024 is a leap year because 2024 is divisible by 4 and not by 100.

So technically, the remainder of 2024 ÷ 4 = 0, but the remainder of 2024 ÷ 100 ≠ 0.

If a year is divisible by 4 and not by 100, it is a leap year.


2022 is not a leap year because 2022 is not divisible by 4.

So technically, the remainder of 2022 ÷ 4 ≠ 0.

If a number is not divisible by 4, it is not a leap year.


1900 is NOT a leap year because although it is divisible by 4, for years that are also divisible by 100, they must be divisible by 400 at the same time.

So technically, the remainder of 1900 ÷ 4 = 0, and that the remainder of 1900 ÷ 100 = 0, but the remainder of 1900 ÷ 400 ≠ 0.

If a number is divisible by 100, it must be also divisible by 400 to be a leap year.


2000 is a leap year because 2000 is divisible by 400.
 If a number is divisible by 100, it must be also divisible by 400 to be a leap year.
#1  With the Clock component
In this concept, we determine the day before March 1 of that year.

the day before March 1 in 2022 is February 28, 2022.

we extract the day of month of February 28, and then find that the day of month is 28.

if the last day of a year in February is 29, it is a leap year. Otherwise, it is not.
#2  Without the Clock component
With the definition of what is a leap year, and determining the year, we can also check whether a year is a leap year just by looking at itself.

if a year is divisible by 400, it passes.

in the next ifelse, if a year is divisible by 100, it does not pass. This is not a bug. If it does not pass the first ifelse statement, it means that it is not divisible by 400. Now, this statement proves that it is divisible by 100, so that means it is a common year.

In the third ifelse statement, if the year is not divisible by 100 or 400, but is divisible by 4, it passes.

Else if the year gets here, it does not pass.
#3  With the Clock component and milliseconds
Prior to method #1, this is also a way to get the day before Marcg but with milliseconds.
#4 + #5  Get day of year for December 31
With Ram's idea, we get the number of day for the last day of year via MakeInstant.
Here is my other way to go.
Tests
Tested successfully on the AI Companion on Xiaomi 5G 11 NE Lite.
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